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Mean Absolute Deviation

By Tina Goosz

Learn about what Mean Absolute Deviation is and how to use it to solve problems. Find the definition, example problems, and practice problems at Thinkster Math.

Why is this concept useful?

This concept is useful when working with datasets where you need to analyze the variability of the data. The higher the Mean Absolute Deviation, the more variable the data.

Where does this concept fit into the curriculum?

Appears in some states as early as 6th grade through High School

How can we use the concept:

Most often when finding Mean Absolute Deviation (henceforth called MAD), we follow a series of steps and not a formula.

The steps:

1) Find the mean of the data set.

2) Find the absolute deviation of each data point by finding the absolute value of the difference between each data point and the mean. (Since we are using absolute value, all these values will be positive.)

3) Find the mean of the deviations.

Sample Math Problems

1. Given the data set: 11, 6, 18, 4, 15, 25 find the mean absolute deviation.

Solution:

Step 1: Find the mean of the data set.

(11 + 6 + 18 + 4 + 15 + 25) 6 = 13.167 (answer rounded to the thousandths place)

Step 2: Find the absolute value of the difference of each data point from the mean.

| 11 - 13.167 | = 2.167

| 6 - 13.167 |= 7.167

| 18 - 13.167 |= 4.833

| 4 - 13.167 | = 9.167

| 15 - 13.167 |= 1.833

| 25 - 13.167 |= 11.833

Step 3: Find the mean of the deviations.

(2.167 + 7.167 + 4.833 + 9.167 + 1.833 + 11.833) 6 = 6.167

2. Given the data set: 30, 49, 17, 17, 46 find the mean absolute deviation.

Solution:

Step 1: Find the mean of the data set.

(30 + 49 + 17 + 17 + 46) 5 = 31.8

Step 2: Find the absolute value of the difference of each data point from the mean.

| 30 - 31.8 |= 1.8

| 49 - 31.8 |= 17.2

| 17 - 31.8 |= 14.8 We will use this twice in step 3 of solving since this data point occurs twice in the data set.

|46 - 31.8|= 14.2

Step 3: Find the mean of the deviations.

(1.8 + 17.2 + 14.8 + 14.8 + 14.2) 5 = 12.56

3. Given the data set: 81, 51, 54, 97, 68, 57, 64 find the mean absolute deviation.

Solution:

Step 1: Find the mean of the data set.

(81 + 51 + 54 + 97 + 68 + 64) 6 = 69.167

Step 2: Find the absolute value of the difference of each data point from the mean.

| 81 - 69.167 | = 11.833

| 51 - 69.167 | = 18.167

| 54 - 69.167 | = 15.167

| 97 - 69.167 |= 27.833

| 68 - 69.167 |= 1.167

| 64 - 69.167 |= 5.167

Step 3: Find the mean of the deviations.

(11.833 + 18.167 + 15.167 + 27.833 + 1.167 + 5.167) 6 = 13.22 (rounded)

4. Given the data set: 57, 45.3, 58.2, 46.7, 65.5 find the mean absolute deviation.

Solution:

Step 1: Find the mean of the data set.

(57 + 45.3 + 58.2 + 46.7 + 65.5) 5 = 54.54

Step 2: Find the absolute value of the difference of each data point from the mean.

| 57 - 54.54 |= 2.46

| 45.3 - 54.54 |= 9.24

| 58.2 - 54.54 |= 3.66

| 46.7 - 54.54 |= 7.84

|65.5 - 54.54 |= 10.96

Step 3: Find the mean of the deviations.

(2.46 + 9.24 + 3.66 + 7.84 + 10.96) 5 = 6.832

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Practice Math Problems

1. Given the data set: 2, 9, 22, 16, 10, 16 find the mean absolute deviation.

2. Given the data set: 12, 38, 37, 25, 12 find the mean absolute deviation.

3. Given the data set: 75, 72, 85, 91, 74, 81 find the mean absolute deviation.

4. Given the data set: 92.4, 90.5, 100.7, 87.7, 93.2 find the mean absolute deviation.

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